5p^2=12-28p

Solution for 5p^2=12-28p equation:

5p^2=12-28p

We move all terms to the left:

5p^2-(12-28p)=0

We add all the numbers together, and all the variables

5p^2-(-28p+12)=0

We get rid of parentheses

5p^2+28p-12=0

a = 5; b = 28; c = -12;
Δ = b2-4ac
Δ = 282-4·5·(-12)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*5}=\frac{-60}{10}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*5}=\frac{4}{10}
=2/5
$